Suppose I have values of a variable that looks like this:
2015-W01 2015-W02 2015-W03 .....
How can I convert them in the following?:
1w2015 2w2015 3w2015 .....
You can do this by using scan to find strings that you need, then concatenate them with cats in the order that you need.
data want;
set have;
str = '2015-W01';
str2 = cats(input(scan(str, 2, 'W'), 8.), 'w', scan(str, 1, '-'));
run;
str str2
2015-W01 1w2015
Let's break it down.
1. Getting the week number first
You want the week number first without a leading zero. Let's consider W to be the separator of out string. We'll get the second word separated by W, which is 01
scan(str, 2, 'W')
But, this still gives a leading zero. We'll convert it into a number which automatically removes the leading zero.
input(scan(str, 2, 'W'), 8.)
Let's move onto the next part: concatenating. cats will automatically convert the number into a string for us, so we don't need to worry about doing a second conversion.
2. Concatenation
Just add w:
cats(input(scan(str, 2, 'W'), 8.), 'w')
This gets us the string:
1w
Now we just need to get the year.
3. Add the year
We'll now look at the whole string again just like we did in part 1, but as a - separated string. The first word in that string is the number, so we'll get that.
scan(str, 1, '-')
4. Putting it all together
For our final code, we get this:
cats(input(scan(str, 2, 'W'), 8.), 'w', scan(str, 1, '-'));