How to upload a file from java to Azure?

I am trying upload a file to Azure from a Java function but i dont get it, i am not sure if my local directories or another variables such as "shareName" or "dirName" or "fileName" i was declared incorrectly

i was a follow the next instructions in the apartated Upload a File: Azure documentation.

At runs my code i was receive the next console output:

DEBUG reactor.netty.resources.PooledConnectionProvider - [id:c341493a, L:/192.168.1.68:56172 - R:wiebs4fefe66q0knduvyeie.file.core.windows.net/52.239.169.232:443] Channel cleaned, now: 0 active connections, 1 inactive connections and 0 pending acquire requests. uploadFile exception: Status code 404, "?<?xml version="1.0" encoding="utf-8"?><Error><Code>ParentNotFound</Code><Message>The specified parent path does not exist. RequestId:f70e845e-401a-0068-66fd-9d44f5000000 Time:2025-03-26T03:17:18.3651535Z</Message></Error>"

I was try use this code extracted from the Azure oficial web site in the Upload a File aparted

the uploadFile metod is the next:

public static Boolean uploadFile(String connectStr, String shareName,
                                    String dirName, String fileName)
{
    try
    {
        ShareDirectoryClient dirClient = new ShareFileClientBuilder()
             .connectionString(connectStr).shareName(shareName)
             .resourcePath(dirName)
             .buildDirectoryClient();

        ShareFileClient fileClient = dirClient.getFileClient(fileName);
        fileClient.create(1024);
        fileClient.uploadFromFile(fileName);
        return true;
    }
    catch (Exception e)
    {
        System.out.println("uploadFile exception: " + e.getMessage());
        return false;
    }
}

and i call the uploadFile method that next way:

String connectionString = "DefaultEndpointsProtocol=https;" +
                "AccountName=wisdfdsfsie;" +
                "AccountKey=Y9vsdfsdfsdfsdffsdfGdQZK8Lz4DAIwi9A==";

        String shareName = "mis-archivos";
        String dirName = "hybris/master/mabe";
        String fileName = "temp/GR_IMPEXP_25-03-2025.csv";

        boolean result = uploadFile(connectionString, shareName, dirName, fileName);

        if (result) {
            System.out.println("Upload Correct.");
        } else {
            System.out.println("Upload Failed....");
        }

i am still not very clear the form of use the variables as shareName, dirName and fileName. I should set a special configuration into my Microsoft Azure Storage Explorer?

in the string fileName i should put the file to transfer to my Azure Storage?

I am should be create a File Shared Resource in the Microsoft Azure Storage Explorer? how to it?

in the dirName i should set the directory trees set into the file shared resources?

I am a little bit confused in how functions the uploadFiles method.

If you look at the error message, you will notice that you are getting the error about the directory not exist. Before you can upload a file in a directory, the directory must be present in that share.

Please see the code below:

public static Boolean uploadFile(String connectStr, String shareName,
                                    String dirName, String fileName)
{
    try
    {
        ShareDirectoryClient dirClient = new ShareFileClientBuilder()
             .connectionString(connectStr).shareName(shareName)
             .resourcePath(dirName)
             .buildDirectoryClient();

        //create directory if it does not exist
        dirClient.createIfNotExists();

        ShareFileClient fileClient = dirClient.getFileClient(fileName);
        fileClient.create(1024);
        fileClient.uploadFromFile(fileName);
        return true;
    }
    catch (Exception e)
    {
        System.out.println("uploadFile exception: " + e.getMessage());
        return false;
    }
}