Separating/Adding lists together for a 2D array

Firstly I want to say thank you in advance for any and all help it's small for some but big for others and you have my gratitude!

I have a list of numbers and need to analyze them in two different ways.
[[ 0, 1, 0, 1, 0], [1, 1, 1, 1, 1], [ 0, 1, 1, 1, 0]]

Firstly I need to add up any 1's and group them but ONLY if they're after each other. For this example:
>>>[[1, 1], [5], [3]]
(if 0 then post a 0)

Then I need to add each row but one column at a time
[[ **0**, 1, 0, 1, 0], [**1**, 1, 1, 1, 1], [ **0**, 1, 1, 1, 0]]
>>>1
(Continues to the next column)
[[ 0, **1**, 0, 1, 0], [1, **1**, 1, 1, 1], [ 0, **1**, 1, 1, 0]]
>>>3
etc, etc.

Thanks again!

I don't know if I understood your question completely, but hopefully this could help:

L = [[ 0, 1, 0, 1, 0], [1, 1, 1, 1, 1], [ 0, 1, 1, 1, 0]]

def get_ones(l : list) -> list:
    res = []
    for sublist in l:
        ones = 0
        subres = []
        for item in sublist:
            if item == 1:
                ones += 1
            else:
                if ones > 0:
                    subres.append(ones)
                ones = 0
        if ones > 0:
            subres.append(ones) # All were ones
        res.append(subres)
    return res

def sum_column_ones(l : list, column) -> int:
    # assertion you have same amount of columns
    ones = 0
    for sublist in l:
        if sublist[column] == 1:
            ones += 1
    return ones
    
print(get_ones(L))

for i in range(len(L[0])): # iterate all columns
    print(f"Ones in column {i}: {sum_column_ones(L, i)}")


[[1, 1], [5], [3]]
Ones in column 0: 1
Ones in column 1: 3
Ones in column 2: 2
Ones in column 3: 3
Ones in column 4: 1