The users.messages.list method requires a string for the labelIds parameter. Is there any way to provide it a string other than entering 'the string'...I want to include this method as part of a for loop cycling through all user defined labels without knowing what they are in advance, but I get a 400 error An API error occurred: <HttpError 400 when requesting https://gmail.googleapis.com/gmail..... this is the format it likes... service.users().messages().list(userId='me',labelIds=['a string']).execute() here is what I want it to do...
try:
# Call the Gmail API
service = build('gmail', 'v1', credentials=creds)
results = service.users().labels().list(userId='me').execute()
labels = results.get('labels', [])
#labels is a list of all system and user defined labels
#need to cycle through all user defined labels and store emails with
#each label
for label in labels:
if label['type']=='user':
name = label['name'] #this is a 'string'
results = service.users().messages().list(
userId='me',
labelIds=[name],
maxResults=2 # Adjust as needed
).execute()
break
I think you should use label['id']
rather than label['name']
. Sometimes, these two have the same value; sometimes, they don't.
Ref: https://developers.google.com/workspace/gmail/api/reference/rest/v1/users.messages/list#http-request
for label in labels:
if label['type'] == 'user':
label_id = label['id'] # Use the label ID, not the name
results = service.users().messages().list(
userId='me',
labelIds=[label_id], # This works!
maxResults=2
).execute()
# Do something with results here
print(f"Messages with label {label['name']}:", results.get('messages', []))
break # Remove break if you want to process all labels