Is there a way to abuse assignment expressions or functional tools to generate the sequence x, f(x), f(f(x)), ... in one line?
Here are some contrived examples to demonstrate:
def iter(x, f, lim=10):
for _ in range(lim):
yield x
x = f(x)
iter(1, lambda x: (2*x)%99)
(This makes one extra function call that goes unused. Ideally this is avoided.)
Another weird idea I had is "One-argument accumulate", even uglier. The idea is to use the binary function but ignore the list elements! It's not a good use of accumulate.
from itertools import accumulate
list(accumulate([None]*10, lambda x,y:2*x, initial=1))
You can use a counter in a list comprehension to determine whether to initialize a number with an assignment expression or to aggregate it with your desired function (assumed to be f = lambda x: (2 * x) % 99 here):
[n := f(n) if i else 1 for i in range(10)]
This returns:
[1, 2, 4, 8, 16, 32, 64, 29, 58, 17]