Is there a problem with calculating triangle area using two vectors instead of three points?

I looked up calculating the area of triangle given three vertices.

func calculate_area_of_triangle(a: Vector2, b: Vector2, c: Vector2) -> float:
    return abs((a.x * (b.y - c.y) + b.x * (c.y - a.y) + c.x * (a.y - b.y)) * 0.5)

func main():
    var points: Array[Vector2] = [Vector2(4.0, 10.0), Vector2(3.0, 7.0), Vector2(8.0, 0.0)]

        calculate_area_of_triangle(points[0], points[1], points[2])

Is there a problem rewriting it like this, using two vectors from a common point?

func calculate_area_of_triangle(a: Vector2, b: Vector2) -> float:
    return abs(a.x*b.y - b.x*a.y)*0.5

func main():
    var points: Array[Vector2] = [Vector2(4.0, 10.0), Vector2(3.0, 7.0), Vector2(8.0, 0.0)]

        calculate_area_of_triangle(points[0]-points[2], points[1]-points[2])

From my tests I haven’t found an issue, but I worry there is something I’m not thinking about.

(I’m using this for calculating an area of polygon. This is for a calculating the area of non-hollow polygon. I take the vertices and subtract the center from them.)

There are no problems. You just calculate area of the same triangle being translated to put one vertex into coordinate origin. Result is correct