Initialize array of pointer to struct using compound literals without being verbose

I would like to initialize a NULL terminated array of pointer to struct using compound literals.

Currently, I achieve this by:

struct object
{
    int data1;
    char data2;
};

struct object *object_array[] =
{
    &(struct object) {1, 2},
    &(struct object) {3, 4},
    &(struct object) {5, 6},
    &(struct object) {7, 8},
    &(struct object) {9, 10},
    NULL,
};

But, specifying (struct object) is very verbose.

Is there a way to make my code look something like this:

struct object
{
    int data1;
    char data2;
};

struct object *object_array[] =
{
    &{1, 2},
    &{3, 4},
    &{5, 6},
    &{7, 8},
    &{9, 10},
    NULL,
};

You could use a temporary helper macro:

struct object
{
    int data1;
    char data2;
};

#define OB(data1, data2)    &(struct object) {data1, data2}

struct object *object_array[] =
{
    OB(1, 2),
    OB(3, 4),
    OB(5, 6),
    OB(7, 8),
    OB(9, 10),
    NULL
};

#undef OB

This is just a more concise way to do what was done in first example.