I reviewed the "similar questions", but those seem to refer to using the full path for ffmpeg to ensure using the same version, which I am already doing so posting my question.
I am using a Mac runnning Sequoia 15.5, python 3, and ffmpeg 4.2.1.
I'm trying to write a script that can convert flac to mp3 320k.
If I use the following command in terminal everything works as intended:
/usr/local/bin/ffmpeg -i "/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.flac" -b:a 320k -map_metadata 0 -id3v2_version 3 "/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.mp3"
But when trying to do the same thing with subprocess.call with the following:
command = ['/usr/local/bin/ffmpeg', '-i', '/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.flac', '-b:a 320k', '-map_metadata 0', '-id3v2_version 3', '/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.mp3']
p = subprocess.call(command)
I get this as a result:
Unrecognized option 'id3v2_version 3'.
Error splitting the argument list: Option not found
If I remove the '-id3v2_version 3', then the subprocess.call results in the following error:
[mp3 @ 0x7fae2c008200] Invalid stream specifier: a 320k.
Why does Terminal understand but subprocess.call doesn't when I've verified I'm using the same version of ffmpeg?
You are passing the options incorrectly. -b:a 320k is not a single argument to the command, otherwise your command line would have enclosed it in quotes ("-b:a 320k"). You need to pass '-b:a' and '320k' as separate arguments, and similarly with the other options that include arguments.
specifically:
command = [
'/usr/local/bin/ffmpeg',
'-i',
'/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.flac',
'-b:a',
'320k',
'-map_metadata',
'0',
'-id3v2_version',
'3',
'/Volumes/MainData/Media/Media Server/_Stage/03 - People Like Us - Aaron Tippin.mp3',
]