The book said that ASLR is activated by default on Linux, but when I try to confirm it, I find a strange problem: when I click the run button in VSCode, it always outputs a fixed stack address and ASLR doesn't work, but when I run the executable file generated by VSCode in bash, ASLR works
The code to check the address of the stack:
#include <stdio.h>
int main() {
long local;
printf("local at %p\n", &local);
return 0;
}
The output of clicking the "Run c/cpp file" button:
local at 0x7fffffffd250
The output of running the executable file in bash（several examples of random addresses):
local at 0x7ffed0965fb0
local at 0x7fff3eff7630
local at 0x7ffc0e083a00
I've checked that ASLR is open on my machine, I want to know what's the difference between clicking the button and running it with bash?
Debuggers temporarily disable ASLR to simplify the debugging process.
This can be done via the personality function. Specifically, passing ADDR_NO_RANDOMIZE to this function does this for the current process.