a
0
a×←5
a
0
(a×←5)
5
a
0
(⎕←a×←5)
5
5
Why does having braces(or a ⎕←) over a modified assignment change the result but the variable is set correctly. I am not able to wrap my head around what is going on here. Should this have the result of the assignment ie. the value of the variable as the output?
As per the documentation, the result of an assignment (the “pass-through” value) is whatever is on the right of the ← — no exceptions. So a×←5 is 5, not 0. The parentheses or ⎕← just coerce the otherwise shy value to be visibly returned.