sqloracle-database

How to find maximum avg


I am trying to display the maximum average salary; however, I can't seem to get it to work.

I can get a list of the average salaries to display with:

select worker_id, avg(salary)
from workers
group by worker_id;

However, when I try to display a list of the maximum average salary with:

select max (avg(salary))
from (select worker_id, avg(salary)
      from workers
      group by worker_id);

it doesn't run. I get an "invalid identifier" error. How do I use the average salary for each worker to find the maximum average for each worker?

Thanks.


Solution

  • Columns resulting from aggregate functions (e.g. avg) usually get arbitrary names. Just use an alias for it, and select on that:

    select max(avg_salary)
    from (select worker_id, avg(salary) AS avg_salary
          from workers
          group by worker_id) As maxSalary;