xpath

XPath - Get node with no child of specific type

XML: <A><B></B></A> or <A></A>

I want to get all A nodes that do not have any B children.

I've tried

/A[not(B)]  
/A[not(exists(B))]

without success

I prefer a solution with the syntax /*[local-name()="A" and .... ], if possible. Any ideas that works?

Clarification. The xml looks like:

<WhatEver>
  <A>
    <B></B>
  </A>
</WhatEver>

or

<WhatEver>
  <A></A>
</WhatEver>
Solution

  • Maybe *[local-name() = 'A' and not(descendant::*[local-name() = 'B'])]?

    Also, there should be only one root element, so for /A[...] you're either getting all your XML back or none. Maybe //A[not(B)] or /*/A[not(B)]?

    I don't really understand why /A[not(B)] doesn't work for you.

    ~/xml% xmllint ab.xml
<?xml version="1.0"?>
<root>
    <A id="1">
            <B/>
    </A>
    <A id="2">
    </A>
    <A id="3">
            <B/>
            <B/>
    </A>
    <A id="4"/>
</root>
~/xml% xpath ab.xml '/root/A[not(B)]'
Found 2 nodes:
-- NODE --
<A id="2">
    </A>
-- NODE --
<A id="4" />