How to get the current url namespace using Django?

I have to build an url dynamically according to the current url. Using the {% url %} tag is the easiest way to do it, but I need the current url namespace to generate the new one dynamically.

How can I get the url namespace attached to the urlconf that leads to the current view?

EDIT : I know I can manually handcraft the url using get_absolute_url but I'd rather avoid it since it's part of a lecture and I would like to demonstrate only one way to build urls.

The students know how to use {% url %}. They are know facing a problem when they have to generate a more complete url based on the current one. The easiest way is to use {% url %} again, with some variations. Since we have named url, we need to know how to get the name of the url that called the current view.

EDIT 2: another use case is to display parts of the base template différently according to the base template. There are other ways to do it (using CSS and {% block %}, but sometime it just nice to be able to remove the tag of the menu entry of base.html if the viewname match the link.

Solution

I don't know how long this feature has been part of Django but as the following article shows, it can be achieved as follows in the view:

   from django.core.urlresolvers import resolve
   current_url = resolve(request.path_info).url_name

If you need that in every template, writing a template request can be appropriate.

Edit: APPLYING NEW DJANGO UPDATE

Following the current Django update:

Django 1.10 (link)

Importing from the django.core.urlresolvers module is deprecated in favor of its new location, django.urls

Django 2.0 (link)

The django.core.urlresolvers module is removed in favor of its new location, django.urls.

Thus, the right way to do is like this:

from django.urls import resolve
current_url = resolve(request.path_info).url_name