How to skip the first argument in $@?

My code:

#!/bin/bash

for i in $@;
    do echo $i;
done;

run script:

# ./script 1 2 3

1
2
3

So, I want to skip the first argument and get:

# ./script 1 2 3

2
3

Use the offset parameter expansion

#!/bin/bash

for i in "${@:2}"; do
    echo $i
done

Example

$ func(){ for i in "${@:2}"; do echo "$i"; done;}; func one two three
two
three