I know that you cannot have a break statement for an OpenMP loop, but I was wondering if there is any workaround while still the benefiting from parallelism. Basically I have 'for' loop, that loops through the elements of a large vector looking for one element that satisfies a certain condition. However there is only one element that will satisfy the condition so once that is found we can break out of the loop, Thanks in advance
for(int i = 0; i <= 100000; ++i)
{
if(element[i] ...)
{
....
break;
}
}
You could try to manually do what the openmp for loop does, using a while loop:
const int N = 100000;
std::atomic<bool> go(true);
uint give = 0;
#pragma omp parallel
{
uint i, stop;
#pragma omp critical
{
i = give;
give += N/omp_get_num_threads();
stop = give;
if(omp_get_thread_num() == omp_get_num_threads()-1)
stop = N;
}
while(i < stop && go)
{
...
if(element[i]...)
{
go = false;
}
i++;
}
}
This way you have to test "go" each cycle, but that should not matter that much. More important is that this would correspond to a "static" omp for loop, which is only useful if you can expect all iterations to take a similar amount of time. Otherwise, 3 threads may be already finished while one still has halfway to got...