How do I make this simple shellcode C program compile from the terminal?

I am trying to compile this using the terminal on Ubuntu 12.04 (Precise Pangolin):

#include <stdio.h>
#include <stdlib.h>

main()
{
    /* Declare argument array */
    char *args[2];

    args[0] = “/bin/bash”;
    args[1] = NULL;

    execve(args[0], args, NULL);

    exit(0);
}

I found this example on Buffer Overflow Primer Part 4 (Disassembling Execve) which also happened to be the one Aleph One used in 'Smashing the Stack for Fun and Profit'. I am aware that much has changed since then. In more simple examples I have used:

gcc -ggdb -mpreferred-stack-boundary=2 -fno-stack-protector filename filename.c

Other times I may include the static utility. It has worked up until I have tried to compile the C code above. The message I receive from the terminal is:

gcc -static -mpreferred-stack-boundary=2 -fno-stack-protector -o shell shell.c

Output:

shell.c: In function ‘main’:
shell.c:9:2: error: stray ‘\342’ in program
shell.c:9:2: error: stray ‘\200’ in program
shell.c:9:2: error: stray ‘\234’ in program
shell.c:9:15: error: expected expression before ‘/’ token
shell.c:9:15: error: stray ‘\342’ in program
shell.c:9:15: error: stray ‘\200’ in program
shell.c:9:15: error: stray ‘\235’ in program

I understand that this is a very simple example and that this error is probably caused by current standard security measures in Linux, but I would like to get around them to practise with this example and more in the future. How can I fix this problem?

You have "smart" quotes around your string literal,

“/bin/bash”;

Try using ordinary quotes ".