I have more than 10 tasks to execute, and the system restrict that there at most 4 tasks can run at the same time.
My task can be started like: myprog taskname
How can I write a bash shell script to run these task. The most important thing is that when one task finish, the script can start another immediately, making the running tasks count remain 4 all the time.
I chanced upon this thread while looking into writing my own process pool and particularly liked Brandon Horsley's solution, though I couldn't get the signals working right, so I took inspiration from Apache and decided to try a pre-fork model with a fifo as my job queue.
The following function is the function that the worker processes run when forked.
# \brief the worker function that is called when we fork off worker processes
# \param[in] id the worker ID
# \param[in] job_queue the fifo to read jobs from
# \param[in] result_log the temporary log file to write exit codes to
function _job_pool_worker()
{
local id=$1
local job_queue=$2
local result_log=$3
local line=
exec 7<> ${job_queue}
while [[ "${line}" != "${job_pool_end_of_jobs}" && -e "${job_queue}" ]]; do
# workers block on the exclusive lock to read the job queue
flock --exclusive 7
read line <${job_queue}
flock --unlock 7
# the worker should exit if it sees the end-of-job marker or run the
# job otherwise and save its exit code to the result log.
if [[ "${line}" == "${job_pool_end_of_jobs}" ]]; then
# write it one more time for the next sibling so that everyone
# will know we are exiting.
echo "${line}" >&7
else
_job_pool_echo "### _job_pool_worker-${id}: ${line}"
# run the job
{ ${line} ; }
# now check the exit code and prepend "ERROR" to the result log entry
# which we will use to count errors and then strip out later.
local result=$?
local status=
if [[ "${result}" != "0" ]]; then
status=ERROR
fi
# now write the error to the log, making sure multiple processes
# don't trample over each other.
exec 8<> ${result_log}
flock --exclusive 8
echo "${status}job_pool: exited ${result}: ${line}" >> ${result_log}
flock --unlock 8
exec 8>&-
_job_pool_echo "### _job_pool_worker-${id}: exited ${result}: ${line}"
fi
done
exec 7>&-
}
You can get a copy of my solution at Github. Here's a sample program using my implementation.
#!/bin/bash
. job_pool.sh
function foobar()
{
# do something
true
}
# initialize the job pool to allow 3 parallel jobs and echo commands
job_pool_init 3 0
# run jobs
job_pool_run sleep 1
job_pool_run sleep 2
job_pool_run sleep 3
job_pool_run foobar
job_pool_run foobar
job_pool_run /bin/false
# wait until all jobs complete before continuing
job_pool_wait
# more jobs
job_pool_run /bin/false
job_pool_run sleep 1
job_pool_run sleep 2
job_pool_run foobar
# don't forget to shut down the job pool
job_pool_shutdown
# check the $job_pool_nerrors for the number of jobs that exited non-zero
echo "job_pool_nerrors: ${job_pool_nerrors}"
Hope this helps!