I need to display a tooltip on a disabled button and remove it on an enabled button. Currently, it works in reverse.
What is the best way to invert this behaviour?
$('[rel=tooltip]').tooltip();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<hr>
<button class="btn" disabled rel="tooltip" data-title="Dieser Link führt zu Google">button disabled</button>
<button class="btn" rel="tooltip" data-title="Dieser Link führt zu Google">button not disabled</button>
Here is a demo
P.S.: I want to keep the disabled
attribute.
Here is some working code: http://jsfiddle.net/mihaifm/W7XNU/200/
$('body').tooltip({
selector: '[rel="tooltip"]'
});
$(".btn").click(function(e) {
if (! $(this).hasClass("disabled"))
{
$(".disabled").removeClass("disabled").attr("rel", null);
$(this).addClass("disabled").attr("rel", "tooltip");
}
});
The idea is to add the tooltip to a parent element with the selector
option, and then add/remove the rel
attribute when enabling/disabling the button.