I'm new to programming and ruby. I'm working on code that deals with a specific Diophantine equation (from an MIT opencourseware problem), and just kind of seeing what I can do with it.
The code produces three arrays and a hash of two of them for a particular linear equation with three variables.
Here's the code:
def diophantine_solutions(x)
#For all x > 1, finds values for a, b, c such that 6a + 9b + 20c = x,
#Creates array of solvable x, unsolvable x,
#Creates hash of solvable x with possible values of a, b, c
nopes=(1..x).to_a #will contain sums with no solutions at the end
yups=[] #has solvalbes
yups_values=[] #solutions for a, b, c
yups_hash={} #sums with the solutions
while x>0
for a in (0..x/6):
for b in (0..x/9):
for c in (0..x/20):
total=6*a + 9*b + 20*c
if total==x
yups<< x
yups_values<< [a, b, c]
end
end
end
end
x=x-1
end
yups_hash=[yups.zip(yups_values)]
yups=yups.uniq
nopes=nopes-yups
puts yups_hash[20]
end
diophantine_solutions(20)
What I'm trying to do now is access the individual hash pairings to make sure they are lining up right, but
puts yups_hash[]
returns nil for any number. Any help? Also, being new as I am, if there are better ways to do anything I've done, I'd appreciate it if you let me know.
It should probably be:
yups_hash = Hash[yups.zip(yups_values)]
With the caveat that I don't know what's supposed be happening, but the yups_hash name implies it should be a hash, not an array with a bunch of arrays in it.
Once there's an actual hash the output for 20 is:
0 0 1
This matches the definition, at least.