I am using subprocess to call another program and save its return values to a variable. This process is repeated in a loop, and after a few thousands times the program crashed with the following error:
Traceback (most recent call last):
File "./extract_pcgls.py", line 96, in <module>
SelfE.append( CalSelfEnergy(i) )
File "./extract_pcgls.py", line 59, in CalSelfEnergy
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
File "/usr/lib/python3.2/subprocess.py", line 745, in __init__
restore_signals, start_new_session)
File "/usr/lib/python3.2/subprocess.py", line 1166, in _execute_child
errpipe_read, errpipe_write = _create_pipe()
OSError: [Errno 24] Too many open files
Code:
cmd = "enerCHARMM.pl -parram=x,xtop=topology_modified.rtf,xpar=lipid27_modified.par,nobuildall -out vdwaals {0}".format(cmtup[1])
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
out, err = p.communicate()
I guess the problem was due to the fact that I was processing an open file with subprocess:
cmd = "enerCHARMM.pl -par param=x,xtop=topology_modified.rtf,xpar=lipid27_modified.par,nobuildall -out vdwaals {0}".format(cmtup[1])
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
Here the cmd variable contain the name of a file that has just been created but not closed. Then the subprocess.Popen
calls a system command on that file. After doing this for many times, the program crashed with that error message.
So the message I learned from this is
Close the file you have created, then process it