awk

AWK to print every nth line from a file

i want to print every Nth line of a file using AWK. i tried modifying the general format:

awk '0 == NR % 4' results.txt

to:

awk '0 == NR % $ct' results.txt

where 'ct' is the number of lines that should be skipped. its not working . can anyone please help me out? Thanks in advance.

Solution

  • You may want to use:

    awk -v patt="$ct" 'NR % patt' results.txt

    Explanation

    Given a file like the following:

    $ cat -n a
     1  hello1
     2  hello2
     3  hello3
     4  hello4
     5  hello5
     ...
    37  hello37
    38  hello38
    39  hello39
    40  hello40

    These are equivalent:

    $ awk 'NR % 7 == 0' a
hello7
hello14
hello21
hello28
hello35
$ ct=7
$ awk -v patt="$ct" 'NR % patt == 0' a
hello7
hello14
hello21
hello28
hello35

    Or even

    $ awk -v patt="$ct" '!(NR % patt)' a

    Note that the syntax NR % n == 0 means: number of line is multiple to n. If we say !(NR % patt), then this is true whenever NR % patt is false, ie, NR is multiple of patt.

    Update

    As you comment you are using Solaris, instead of default awk use the following:

    /usr/xpg4/bin/awk