Printing elements of dictionary line by line

I have a dictionary in a file and i should write a python code to print the keys and values in seperate lines.(without using .keys() and .values().

For eg: dict={"the":"1", "and":"2"} should return as

the:1          
and:2 

Here is my code i tried. I am new to python dictionary. Please help me fix this.

dict2 = {}

f= open("dict.txt", 'r')
    for line in f:
        it = line.split()
        k, v = it[0], it[1:]
        dict2[k] = v
return (dict2)

If you are trying to print the key values out of a dictionary in the same order as they appear in the file using a standard dict that won't work (python dict objects don't maintain order). Assuming you want to print by the value of the dicts values...

lines = ["the 1", "and 2"]
d = {}

for l in lines:
    k, v = l.split()
    d[k] = v

for key in sorted(d, key=d.get, reverse=True):
    print ":".join([key, d[key]])

assuming you can use lambda and string concatenation.

lines = ["the 1", "and 2"]
d = {}

for l in lines:
    k, v = l.split()
    d[k] = v

for key in sorted(d, key=lambda k: d[k], reverse=True):
    print key + ":" + d[key]

with out lambda

for value, key in sorted([(d[k], k) for k in d], reverse=True):
    print key + ":" + value

to make a function out of it

def lines_to_dict(lines):
    return_dict = {}
    for line in lines:
        key, value = line.split()
        return_dict[key] = value

    return return_dict

if __name__ == "__main__":

    lines = ["the 1", "and 2"]
    print lines_to_dict(lines)