I have two result sets like this:
// Result 1
[
{ value: "0", display: "Jamsheer" },
{ value: "1", display: "Muhammed" },
{ value: "2", display: "Ravi" },
{ value: "3", display: "Ajmal" },
{ value: "4", display: "Ryan" }
]
// Result 2
[
{ value: "0", display: "Jamsheer" },
{ value: "1", display: "Muhammed" },
{ value: "2", display: "Ravi" },
{ value: "3", display: "Ajmal" },
]
The final result I need is the difference between these arrays – the final result should be like this:
[{ value: "4", display: "Ryan" }]
Is it possible to do something like this in JavaScript?
Using only native JS, something like this will work:
const a = [{ value:"0", display:"Jamsheer" }, { value:"1", display:"Muhammed" }, { value:"2", display:"Ravi" }, { value:"3", display:"Ajmal" }, { value:"4", display:"Ryan" }];
const b = [{ value:"0", display:"Jamsheer", $$hashKey:"008" }, { value:"1", display:"Muhammed", $$hashKey:"009" }, { value:"2", display:"Ravi", $$hashKey:"00A" }, { value:"3", display:"Ajmal", $$hashKey:"00B" }];
// A comparer used to determine if two entries are equal.
const isSameUser = (a, b) => a.value === b.value && a.display === b.display;
// Get items that only occur in the left array,
// using the compareFunction to determine equality.
const onlyInLeft = (left, right, compareFunction) =>
left.filter(leftValue =>
!right.some(rightValue =>
compareFunction(leftValue, rightValue)));
const onlyInA = onlyInLeft(a, b, isSameUser);
const onlyInB = onlyInLeft(b, a, isSameUser);
const result = [...onlyInA, ...onlyInB];
console.log(result);