pythonpython-3.xurllib2urllibpercent-encoding

Python percent encoding only certain characters in a URL

I have to percent encode only # character if it appears in a given url. I know that we can encode a URL using urllib.quote. It takes a safe keyword to set a particular character to be safe for the URL. I am looking for something like:

a = 'http://localhost:8001/3.0/lists/list_1.localhost.org/roster/owner#iammdkdkf'
b = urllib.quote(a,unsafe='#')

Regards.

Solution

  • How about a.replace('#','%23')?