Hollow Diamond in Python with recursion

I've been trying to make a diamond out of forward and backwards slashes, so far I have this piece of code:

def upper_diamond(level,length):
if level <=length:
    print(" " * (length - level), end="")
    print("/", end="")
    print(" " * 2 * (level-1), end=" ")
    print("\\")
    upper_diamond(level + 1,length)

def lower_diamond(level,length):


def diamond(length):
    upper_diamond(1,length)

diamond(4)

and when I print it comes out as such:

   / \
  /   \
 /     \
/       \

I want to make a complete diamond and making the bottom part is stumping me, how do I make the bottom half print with the rest of the diamond?

Basing off your code, you can replicate the same behavior adjusting the offsets (changed end after spacing section to empty string to avoid opened edges):

def upper_diamond (level, length):
    if level <= length:
        print(' ' * (length - level), end='')
        print('/', end='')
        print(' ' * 2 * (level - 1), end='')
        print('\\')
        upper_diamond(level + 1, length)

def lower_diamond (level, length):
    if level <= length:
        print(' ' * (level - 1), end='')
        print('\\', end='')
        print(' ' * 2 * (length - level), end='')
        print('/')
        lower_diamond(level + 1, length)

def diamond(length):
    upper_diamond(1, length)
    lower_diamond(1, length)

diamond(4)

Outputs:

   /\
  /  \
 /    \
/      \
\      /
 \    /
  \  /
   \/