Like below, i want to stop the literal by something like break
var numbers = [1,2,3,4]
numbers.forEach {
if $0 % 2 == 0 {
break
}
}
forEach
is not a loop (it is a block passed to a loop, but not a loop itself), or more accurately, forEach
is not part of Swift's Control Flow. Which is why you can't use break
or continue
.
Just use a for-in loop.
Example :
var numbers = [ 1,2,3,4]
func firstEvenNumber(inArray array: [Int]) -> Int? {
var firstMatch : Int?
for number in numbers {
if (number % 2) == 0 {
firstMatch = number
break
}
}
return firstMatch
}
firstEvenNumber(inArray: numbers) // 2
You can use return
inside the forEach
closure, but it does not break the loop, it only returns the block in the current pass.
var numbers = [ 1,2,3,4]
func evenNumbers(inArray: [Int]) -> [Int] {
var matches : [Int] = []
numbers.forEach{
if $0 % 2 == 0 {
matches.append($0)
// early return on even numbers
// does not stop forEach
// comparable to a continue in a for in loop
return
}
// only reached on uneven numbers
}
return matches
}
evenNumbers(numbers) // [2,4]