bashshelldo-while

syntax error near unexpected token `<'


StudentAnwser=()
inputScriptFile=001.sh

while IFS= read -r line;
do
    StudentAnwser+=( "$line" )
done < <( sh $inputScriptFile test.txt )

it returns a error

foo.sh: line 22: syntax error near unexpected token `<'
foo.sh: line 22: `  done < <( sh $inputScriptFile test.txt )'

what's wrong with that? I follow the solution from other question for reading line from result


Solution

  • You get the error because process substitution (the <(some command) part) is not a standard feature (defined in POSIX) in sh, which means it may work on some OS but may not in others or in the same OS with different configuration.

    You clarified that you have #!/bin/bash at the top of your script, but I guess you still run the script via sh foo.sh, as such, #!/bin/bash will be ignored and the script is interpreted by sh.

    I assume your default shell is bash (run echo $SHELL), so all problems are gone if you paste the script in terminal and execute.

    ==== UPDATE ====

    Possible solution if my assumption is correct:

    Leave #!/bin/bash as it is, make your script an executable by chmod +x foo.sh. Then run it directly by ./foo.sh