So I have a simpler variation of the Einstein/Zebra puzzle in Prolog.
And I came up with this possible solution:
b_setval(T_age, Var).
friends(L) :-
L = [person(A1, B1, T_age), person(A2, B2, C2), person(A3, B3, T_age+3)],
:
:
member(person(_,yang,T_age+3),L),
member(person(_,_,18),L).
But my query friends(L). - false.
only returns false
as stated.
What am I doing wrong?
After following the answer of @luker, you can check your answer
friends(L) :-
% 1
L = [person(ada, _, Ta), person(ama, _, _), person(ana, _, _)],
% 2
member(person(_,_,15), L),
member(person(_,_,17), L),
member(person(_,_,18), L),
% 3
member(person(_, chang, _), L),
% 4
member(person(_, yang, Ty), L), Ty is Ta + 3,
% 5
member(person(_, thatcher, 17), L).
Interesting, this produces 2 results, which is weird for this kind of problem.