When writing some code using UndecidableInstances
earlier, I ran into something that I found very odd. I managed to unintentionally create some code that typechecks when I believed it should not:
{-# LANGUAGE FlexibleInstances #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE UndecidableInstances #-}
data Foo = Foo
class ConvertFoo a b where
convertFoo :: a -> b
instance (ConvertFoo a Foo, ConvertFoo Foo b) => ConvertFoo a b where
convertFoo = convertFoo . (convertFoo :: a -> Foo)
evil :: Int -> String
evil = convertFoo
Specifically, the convertFoo
function typechecks when given any input to produce any output, as demonstrated by the evil
function. At first, I thought that perhaps I managed to accidentally implement unsafeCoerce
, but that is not quite true: actually attempting to call my convertFoo
function (by doing something like evil 3
, for example) simply goes into an infinite loop.
I sort of understand what’s going on in a vague sense. My understanding of the problem is something like this:
ConvertFoo
that I have defined works on any input and output, a
and b
, only limited by the two additional constraints that conversion functions must exist from a -> Foo
and Foo -> b
.convertFoo :: a -> Foo
is picking the very definition of convertFoo
itself, since it’s the only one available, anyway.convertFoo
calls itself infinitely, the function goes into an infinite loop that never terminates.convertFoo
never terminates, the type of that definition is bottom, so technically none of the types are ever violated, and the program typechecks.Now, even if the above understanding is correct, I am still confused about why the whole program typechecks. Specifically, I would expect the ConvertFoo a Foo
and ConvertFoo Foo b
constraints to fail, given that no such instances exist.
I do understand (at least fuzzily) that constraints don’t matter when picking an instance—the instance is picked based solely on the instance head, then constraints are checked—so I could see that those constraints might resolve just fine because of my ConvertFoo a b
instance, which is about as permissive as it can possibly be. However, that would then require the same set of constraints to be resolved, which I think would put the typechecker into an infinite loop, causing GHC to either hang on compilation or give me a stack overflow error (the latter of which I’ve seen before).
Clearly, though, the typechecker does not loop, because it happily bottoms out and compiles my code happily. Why? How is the instance context satisfied in this particular example? Why doesn’t this give me a type error or produce a typechecking loop?
I wholeheartedly agree that this is a great question. It speaks to how our intuitions about typeclasses differ from the reality.
To see what is going on here, going to raise the stakes on the
type signature for evil
:
data X
class Convert a b where
convert :: a -> b
instance (Convert a X, Convert X b) => Convert a b where
convert = convert . (convert :: a -> X)
evil :: a -> b
evil = convert
Clearly the Covert a b
instance is being chosen as there is only
one instance of this class. The typechecker is thinking something like
this:
Convert a X
is true if...
Convert a X
is true [true by assumption]Convert X X
is true
Convert X X
is true if...
Convert X X
is true [true by assumption]Convert X X
is true [true by assumption]Convert X b
is true if...
Convert X X
is true [true from above]Convert X b
is true [true by assumption]The typechecker has surprised us. We do not expect Convert X X
to be
true as we have not defined anything like it. But (Convert X X, Convert X X) => Convert X X
is a kind of tautology: it is
automatically true and it is true no matter what methods are defined in the class.
This might not match our mental model of typeclasses. We expect the
compiler to gawk at this point and complain about how Convert X X
cannot be true because we have defined no instance for it. We expect
the compiler to stand at the Convert X X
, to look for another spot
to walk to where Convert X X
is true, and to give up because there
is no other spot where that is true. But the compiler is able to
recurse! Recurse, loop, and be Turing-complete.
We blessed the typechecker with this capability, and we did it with
UndecidableInstances
. When the documentation states that it is
possible to send the compiler into a loop it is easy to assume the
worst and we assumed that the bad loops are always infinite loops. But
here we have demonstrated a loop even deadlier, a loop that
terminates – except in a surprising way.
(This is demonstrated even more starkly in Daniel's comment:
class Loop a where
loop :: a
instance Loop a => Loop a where
loop = loop
.)
This is the exact sort of situation that UndecidableInstances
allows. If we turn that extension off and turn FlexibleContexts
on
(a harmless extension that is just syntactic in nature), we get a
warning about a violation of one of the Paterson
conditions:
...
Constraint is no smaller than the instance head
in the constraint: Convert a X
(Use UndecidableInstances to permit this)
In the instance declaration for ‘Convert a b’
...
Constraint is no smaller than the instance head
in the constraint: Convert X b
(Use UndecidableInstances to permit this)
In the instance declaration for ‘Convert a b’
"No smaller than instance head," although we can mentally rewrite it as "it is possible this instance will be used to prove an assertion of itself and cause you much anguish and gnashing and typing." The Paterson conditions together prevent looping in instance resolution. Our violation here demonstrates why they are necessary, and we can presumably consult some paper to see why they are sufficient.
As for why the program at runtime infinite loops: There is the boring
answer, where evil :: a -> b
cannot but infinite loop or throw an
exception or generally bottom out because we trust the Haskell
typechecker and there is no value that can inhabit a -> b
except
bottom.
A more interesting answer is that, since Convert X X
is
tautologically true, its instance definition is this infinite loop
convertXX :: X -> X
convertXX = convertXX . convertXX
We can similarly expand out the Convert A B
instance definition.
convertAB :: A -> B
convertAB =
convertXB . convertAX
where
convertAX = convertXX . convertAX
convertXX = convertXX . convertXX
convertXB = convertXB . convertXX
This surprising behavior, and how constrained instance resolution (by default without extensions) is meant to be as to avoid these behaviors, perhaps can be taken as a good reason for why Haskell's typeclass system has yet to pick up wide adoption. Despite its impressive popularity and power, there are odd corners to it (whether it is in documentation or error messages or syntax or maybe even in its underlying logic) that seem particularly ill fit to how we humans think about type-level abstractions.