I'm learning Golang so I can rewrite some of my shell scripts.
I have URL's that look like this:
https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value
I want to extract the following part:
https://example-1.example.com/a/c482dfad3573acff324c/list.txt
In a shell script I would do something like this:
echo "$myString" | grep -o 'http://.*.txt'
What is the best way to do the same thing in Golang, only by using the standard library?
There are a few options:
// match regexp as in question
pat := regexp.MustCompile(`https?://.*\.txt`)
s := pat.FindString(myString)
// everything before the ?
s, _, _ := strings.Cut(myString, "?")
// parse and clear query string
u, err := url.Parse(myString)
u.RawQuery = ""
s := u.String()
The last option is the best because it will handle all possible corner cases.