Python Pandas find all rows where all values are NaN

So I have a dataframe with 5 columns. I would like to pull the indices where all of the columns are NaN. I was using this code:

nan = pd.isnull(df.all)

but that is just returning false because it is logically saying no not all values in the dataframe are null. There are thousands of entries so I would prefer to not have to loop through and check each entry. Thanks!

It should just be:

df.isnull().all(1)

The index can be accessed like:

df.index[df.isnull().all(1)]

Demonstration

np.random.seed([3,1415])
df = pd.DataFrame(np.random.choice((1, np.nan), (10, 2)))
df

idx = df.index[df.isnull().all(1)]
nans = df.ix[idx]
nans

---

Timing

code

np.random.seed([3,1415])
df = pd.DataFrame(np.random.choice((1, np.nan), (10000, 5)))