Consider the following hierarchy of structs:
struct I1 {
virtual void doit() = 0;
};
struct I2 {
virtual void doit(int) = 0;
};
struct I12 : I1, I2 {
using I1::doit;
using I2::doit;
};
struct Derived : I12 {
void doit(int) override {}
};
Compiling this (using clang
, or g++
with -Woverloaded-virtual
) gives me a warning:
'Derived::doit' hides overloaded virtual function [-Woverloaded-virtual]
However, if I change I12
to the following, it compiles fine under clang
, while g++ -Woverloaded-virtual
still gives a warning:
struct I12 : I1, I2 {
using I1::doit;
void doit(int) override = 0;
};
Where is the difference between using I2::doit
and void doit(int) override = 0
? Naively, I would have thought that the former is sufficient to inform the compiler that I am aware that there are two versions of doit
.
It complains that doit
is hidden in Derived
. A fix:
struct Derived : I12 {
using I12::doit; // Bring all doit declarations from I12 into this scope.
void doit(int) override {}
};