// file
var a = "a" // what if this is import statement?
// jscodeshift
export default (file, api) => {
const j = api.jscodeshift;
const root = j(file.source);
root.find(j.VariableDeclaration)
.insertBefore("use strict");
return root.toSource();
}
How does insertBefore work if the first line of code differs across the files. e.g. (variable declaration, import statements)
It looks like you have to "cast"
the node to the jscodeshift
.
A solution is:
export default (file, api) => {
const j = api.jscodeshift
const root = j(file.source)
j(root.find(j.VariableDeclaration).at(0).get())
.insertBefore(
'"use strict";'
)
return root.toSource()
}
EDIT
For your clarification.
If you want to insert use strict
at the beginning of the file no matter what:
export default (file, api) => {
const j = api.jscodeshift
const s = '"use strict";';
const root = j(file.source)
root.get().node.program.body.unshift(s);
return root.toSource()
}
If you want to add use strict
after the import
declaration, if any:
export default (file, api) => {
const j = api.jscodeshift
const s = '"use strict";';
const root = j(file.source);
const imports = root.find(j.ImportDeclaration);
const n = imports.length;
if(n){
//j(imports.at(0).get()).insertBefore(s); // before the imports
j(imports.at(n-1).get()).insertAfter(s); // after the imports
}else{
root.get().node.program.body.unshift(s); // beginning of file
}
return root.toSource();
}