insert into hospital_image
select 'HospitalImage',
lo_from_bytea(1,decode('/9j/4AAQSkZJRgABAQEA3ADcAAD','base64')),
'jpg',
'123'
where not exists (select null from pg_largeObject where loid=1);
CREATE TABLE hospital_image (
key character varying(30) NOT NULL,
image oid NOT NULL,
mime_type character varying(30) NOT NULL,
version numeric(8,0) NOT NULL,
CONSTRAINT
pk_hospital_image PRIMARY KEY (key)
) WITH ( OIDS=FALSE );
ALTER TABLE
hospital_image OWNER TO postgres;
Here in the above Statement we are supplying the loid manually as 1. Instead we want to get the loid dynamically using lo_create(0). When I use lo_create(0) as per the Postgres docs, Iget an exception.
I used both lo_creat(-1) and lo_create(0). Both doesn't work. It is saying loid exists already. how to use the above functions in my query.
My SQL statement for including a variable OID is:
INSERT INTO hospital_image (key, image, mime_type, version)
VALUES ('MainLogoImage99999',
lo_from_bytea(lo_create(0),
decode('/9j4AAQSkZJRgABAQEA3ADcAAD',
'base64')),
'jpg',
123);
The error message is:
ERROR: duplicate key value violates unique constraint "pg_largeobject_metadata_oid_index"
SQL state: 23505
Detail: Key (oid)=(34773) already exists.
Both lo_creat(-1) (the argument doesn't matter) and lo_create(0) will create a new large object and return its OID.
lo_create(-1) is the same as lo_create(4294967295) – OIDs are unsigned 4-byte integers.
lo_from_bytea also creates a new large object, so if you pass it the result from lo_create, it complains that it cannot create a large object with the same number again.
Just pass 0 instead of lo_create(0) as the first argument to lo_from_bytea.