I am trying this:
std::cout << boost::lexical_cast<std::string>(0.0009) << std::endl;
and expecting the output to be:
0.0009
But the output is:
0.00089999999999999998
g++ version: 5.4.0, Boost version: 1.66
What can I do to make it print what it's been given.
You can in fact override the default precision:
#include <boost/lexical_cast.hpp>
#ifdef BOOST_LCAST_NO_COMPILE_TIME_PRECISION
# error unsupported
#endif
template <> struct boost::detail::lcast_precision<double> : std::integral_constant<unsigned, 5> { };
#include <string>
#include <iostream>
int main() {
std::cout << boost::lexical_cast<std::string>(0.0009) << std::endl;
}
Prints
0.0009
However, this is both not supported (detail::
) and not flexible (all doubles will come out this way now).
The problem is loss of accuracy converting from the decimal representation to the binary representation. Instead, use a decimal float representation:
#include <boost/lexical_cast.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <string>
#include <iostream>
using Double = boost::multiprecision::cpp_dec_float_50;
int main() {
Double x("0.009"),
y = x*2,
z = x/77;
for (Double v : { x, y, z }) {
std::cout << boost::lexical_cast<std::string>(v) << "\n";
std::cout << v << "\n";
}
}
Prints
0.009
0.009
0.018
0.018
0.000116883
0.000116883