linuxbashshellcurl

cURL: how can I return 0 if status is 200?

How can I return 0 when the response status is 200?

Right now I'm able to get the status, e.g., 200 with the following command:

curl -LI http://google.com -o /dev/null -w '%{http_code}\n' -s

But I need to turn this 200 in a return of 0.

How can I achieve this?

I tried the following command, but it doesn't return:

if [$(curl -LI http://google.com -o /dev/null -w '%{http_code}\n' -s) == "200"]; then echo 0
Solution

  • It looks like you need some spaces and a fi. This works for me:

    if [ $(curl -LI http://google.com -o /dev/null -w '%{http_code}\n' -s) == "200" ]; then echo 0; fi