Suppose I have a simple struct
:
struct S {
int index;
const std::vector<int>& vec;
};
I want to write a pretty printer for GDB that would display vec[index]
for an object of type S
.
This is how I do it now:
class SPrinter:
def __init__(self, name, val):
self.val = val
def to_string(self):
i = int(self.val['index'])
ptr = self.val['vec']['_M_impl']['_M_start'] + i
return str(ptr.dereference())
Is there a simpler way to access the given element of std::vector
? Is it possible to call operator[]
(in GDB I can do p s.vec[0]
and get what I want)? I'd like my printer to be independent of the particular implementation of std::vector
.
After reading this answer, I came up with the following solution:
def get_vector_element(vec, index):
type = gdb.types.get_basic_type(vec.type)
return gdb.parse_and_eval('(*(%s*)(%s))[%d]' % (type, vec.address, index))
class SPrinter(object):
def __init__(self, name, val):
self.val = val
def to_string(self):
return get_vector_element(self.val['vec'], int(self.val['index']))