I have a hash with values that's an array. How do I delete repeated elements in the array and the corresponding ids in the most performant way?
Here's an example of my hash
hash = {
"id" => "sjfdkjfd",
"name" => "Field Name",
"type" => "field",
"options" => ["Language", "Question", "Question", "Answer", "Answer"],
"option_ids" => ["12345", "23456", "34567", "45678", "56789"]
}
The idea I have is something like this
hash["options"].each_with_index { |value, index |
h = {}
if h.key?(value)
delete(value)
delete hash["option_ids"].delete_at(index)
else
h[value] = index
end
}
The result should be
hash = {
"id" => "sjfdkjfd",
"name" => "Field Name",
"type" => "field",
"options" => ["Language", "Question", "Answer"],
"option_ids" => ["12345", "23456", "45678"]
}
I know I have to put into consideration that when I delete the values of the options and option_ids the indexes of those values are going to change. But not sure how to do this
The first idea I had is to zip the values and call uniq, then think a way to return back to the initial form:
h['options'].zip(h['option_ids']).uniq(&:first).transpose
#=> [["Language", "Question", "Answer"], ["12345", "23456", "45678"]]
h['options'], h['option_ids'] = h['options'].zip(h['option_ids']).uniq(&:first).transpose
h #=> {"id"=>"sjfdkjfd", "name"=>"Field Name", "type"=>"field", "options"=>["Language", "Question", "Answer"], "option_ids"=>["12345", "23456", "45678"]}
These are the steps:
h['options'].zip(h['option_ids'])
#=> [["Language", "12345"], ["Question", "23456"], ["Question", "34567"], ["Answer", "45678"], ["Answer", "56789"]]
h['options'].zip(h['option_ids']).uniq(&:first)
#=> [["Language", "12345"], ["Question", "23456"], ["Answer", "45678"]]