Lets say I have an expensive operation expensive(x: int) -> int
and the following list comprehension:
# expensive(x: int) -> int
# check(x: int) -> bool
[expensive(i) for i in range(LARGE_NUMBER) if check(expensive(i))]
If I want to avoid running expensive(i)
twice for each i
, is there any way to save it's value with list comprehension?
Using the walrus:
[cache for i in range(LARGE_NUMBER) if check(cache := expensive(i))]