I am trying to convert a (variable length) Hex String to Signed Integer (I need either positive or negative values).
[Int16] [int 32] and [int64] seem to work fine with 2,4+ byte length Hex Strings but I'm stuck with 3 byte strings [int24] (no such command in powershell).
Here's what I have now (snippet):
$start = $mftdatarnbh.Substring($DataRunStringsOffset+$LengthBytes*2+2,$StartBytes*2) -split "(..)"
[array]::reverse($start)
$start = -join $start
if($StartBytes*8 -le 16){$startd =[int16]"0x$($start)"}
elseif($StartBytes*8 -in (17..48)){$startd =[int32]"0x$($start)"}
else{$startd =[int64]"0x$($start)"}
With the above code, a $start value of "D35A71" gives '13851249' instead of '-2925967'. I tried to figure out a way to implement two's complement but got lost. Any easy way to do this right?
Thank you in advance
Edit: Basically, I think I need to implement something like this:
int num = (sbyte)array[0] << 16 | array[1] << 8 | array[2];
as seen here.
Just tried this:
$start = "D35A71"
[sbyte]"0x$($start.Substring(0,2))" -shl 16 -bor "0x$($start.Substring(2,2))" -shl 8 -bor "0x$($start.Substring(4,2))"
but doesn't seem to get the correct result :-/
To parse your hex.-number string as a negative number you can use [bigint] (System.Numerics.BigInteger):
# Since the most significant hex digit has a 1 as its most significant bit
# (is >= 0x8), it is parsed as a NEGATIVE number.
# To force unconditional interpretation as a positive number, prepend '0'
# to the input hex string.
PS> [bigint]::Parse('D35A71', 'AllowHexSpecifier')
-2925967
You can cast the resulting [bigint] instance back to an [int] (System.Int32).
Note:
The result is a negative number, because the most significant hex digit of the hex input string is >= 0x8 (binary 1000), i.e. has its high bit set (meaning: the most significant of the 4 bits that make up a given hex digit is 1).
[bigint] to unconditionally interpret a hex. input string as a positive number, prepend 0.The internal two's complement representation of a resulting negative number is performed at byte boundaries, so that a given hex number with an odd number of digits (i.e. if the first hex digit is a "half byte") has the missing half byte filled with 1 bits.
Therefore, a hex-number string whose most significant digit is >= 0x8 (parses as a negative number) results in the same number as prepending one or more Fs (0xF == 1111) to it; e.g., the following calls all result in -2048:
[bigint]::Parse('800', 'AllowHexSpecifier'),
[bigint]::Parse('F800', 'AllowHexSpecifier'),
[bigint]::Parse('FF800', 'AllowHexSpecifier'), ...
See the docs for details about the parsing logic.
Examples:
# First digit (7) is < 8 (high bit NOT set) -> positive number
[bigint]::Parse('7FF', 'AllowHexSpecifier') # -> 2047
# First digit (8) is >= 8 (high bit IS SET) -> negative number
[bigint]::Parse('800', 'AllowHexSpecifier') # -> -2048
# Prepending additional 'F's to a number that parses as
# a negative number yields the *same* result
[bigint]::Parse('F800', 'AllowHexSpecifier') # -> -2048
[bigint]::Parse('FF800', 'AllowHexSpecifier') # -> -2048
# ...
# Starting the hex-number string with '0'
# *unconditionally* makes the result a *positive* number
[bigint]::Parse('0800', 'AllowHexSpecifier') # -> 2048