Trying to figure out what the proper way to plug in my data is. Any help? Doing it in the way seen here results in integer without a cast. I've tried this a few ways but never quite got the hand of it.
lzo_bytep SERV_DATA_SEND = "702D31FA78809907133F1256459ABFECA9769AEAB65F3F125658";
in_len = IN_LEN;
lzo_memset(in,SERV_DATA_SEND,strlen(SERV_DATA_SEND));
printf("memset: %s\n\n", in);
To prepare the data in a buffer, you should use lzo_memcpy(in, SERV_DATA_SEND, strlen(SERV_DATA_SEND))
, which accepts chars in its second parameter.
pub unsafe extern "C" fn lzo_memcpy(
dst: *mut c_void,
src: *const c_void,
len: lzo_uint
) -> *mut c_void
In lzo_memset()
, the second parameter accepts an integer.
pub unsafe extern "C" fn lzo_memset(
buf: *mut c_void,
c: c_int,
len: lzo_uint
) -> *mut c_void
For example, if you want to clear the buffer, you can use the code below. It will set all the blocks to zero.
lzo_memset(in,0,in_len);
Check out the overlap.c and simple.c example in http://www.oberhumer.com/opensource/lzo/#download