An example I came up was something like this:
identified_characters = ["a","c","f","h","l","o"]
word = "alcachofa#"
if any(character in word for character not in identified_characters):
print("there are unidentified characters inside the word")
else:
print("there aren't unidentified characters inside the word")
but the not brings a syntax error, so I was thinking that if there was an out (opposite of in I guess) function theoretically you could change the not in and keep the syntax.
I also thought the logic of the given result should be the opposite of the any function, but looking up I saw that ppl came out that the opposite of any should be not all, in which case wouldn't work here.
You can't loop over every possible item not in identified_characters; there are unaccountably many. That doesn't even make sense in concept.
To achieve what you want (checking if there are unidentified characters (characters not in identified_characters) in word), you will have to loop over word, not the complement of identified_characters.
identified_characters = {"a", "c", "f", "h", "l", "o"}
word = "alcachofa#"
if any(character not in identified_characters for character in word):
print("there are unidentified characters inside the word")
else:
print("there aren't unidentified characters inside the word")