What is reason to use is operator in TypeScript in this case?
type Species = "cat" | "dog";
interface Pet {
species: Species
}
interface Cat extends Pet {
}
function petIsCat(pet: Pet): pet is Cat {
return pet.species === "cat";
}
Why to use pet is Cat
instead boolean
if body returns bool type?
boolean is just a data type while 'is' operator is used for type-testing. Let me change your example a little bit:
type Species = 'cat' | 'dog';
interface Pet {
species: Species;
}
class Cat implements Pet {
public species: Species = 'cat';
public meow(): void {
console.log('Meow');
}
}
function petIsCat(pet: Pet): pet is Cat {
return pet.species === 'cat';
}
function petIsCatBoolean(pet: Pet): boolean {
return pet.species === 'cat';
}
const p: Pet = new Cat();
p.meow(); // ERROR: Property 'meow' does not exist on type 'Pet'.
if (petIsCat(p)) {
p.meow(); // now compiler knows for sure that the variable is of type Cat and it has meow method
}
if (petIsCatBoolean(p)) {
p.meow(); // ERROR: Property 'meow' does not exist on type 'Pet'.
}
Of course you can use type casting:
(<Cat>p).meow(); // no error
(p as Cat).meow(); // no error
But it depends on the scenario.
Docs: