I'm trying to run this line in Scheme:
(let ((x y) (y x)) (set! x x) (set! y y))
where at the start of the program x is defined to be 1 and y is defined to be 2. I want the output to be x=2 and y=1 but I get x=1 and y=2
Appreciate your help!
My end goal is to switch their values only with commands, not with temporary variables
It looks like racket supports set!-values, so you can swap your variables without using any explicit temporary variables like so:
(define x 1)
(define y 2)
(set!-values (x y) (values y x))
;;; x is now 2 and y is 1
(It's even the example in the linked documentation)