I have the following variant:
typedef boost::variant<int, float, bool> TypeVariant;
And I want to create a visitor to convert a int
or float
type to a bool
type.
struct ConvertToBool : public boost::static_visitor<TypeVariant> {
TypeVariant operator()(int a) const {
return (bool)a;
}
TypeVariant operator()(float a) const {
return (bool)a;
}
};
However this is giving me the error message:
'TypeVariant ConvertToBool::operator ()(float) const': cannot convert argument 1 from 'T' to 'float'
What is the correct way of allowing a visitor to only apply to certain types?
Just include the missing overload:
#include <boost/variant.hpp>
#include <iostream>
using TypeVariant = boost::variant<int, float, bool>;
struct ConvertToBool {
using result_type = TypeVariant;
TypeVariant operator()(TypeVariant const& v) const {
return boost::apply_visitor(*this, v);
}
TypeVariant operator()(int a) const { return a != 0; }
TypeVariant operator()(float a) const { return a != 0; }
TypeVariant operator()(bool a) const { return a; }
} static constexpr to_bool{};
int main() {
using V = TypeVariant;
for (V v : {V{}, {42}, {3.14f}, {true}}) {
std::cout << v << " -> " << std::boolalpha << to_bool(v) << "\n";
}
}
In more general cases you can supply a catch-all template overload:
template <typename T> TypeVariant operator()(T const& a) const {
return static_cast<bool>(a);
}
In fact in your trivial case that's all you needed anyways:
#include <boost/variant.hpp>
#include <iostream>
using TypeVariant = boost::variant<int, float, bool>;
struct ConvertToBool {
using result_type = TypeVariant;
TypeVariant operator()(TypeVariant const& v) const {
return boost::apply_visitor(*this, v);
}
template <typename T> TypeVariant operator()(T const& a) const {
return static_cast<bool>(a);
}
} static constexpr to_bool{};
int main() {
using V = TypeVariant;
for (V v : { V{}, { 42 }, { 3.14f }, { true } }) {
std::cout << v << " -> " << std::boolalpha << to_bool(v) << "\n";
}
}
Still prints
0 -> false
42 -> true
3.14 -> true
true -> true