javascriptfunctional-programmingramda.jspointfree

Pointfree dynamic function composition

I'm trying to refactor this function to be pointfree.

function siblings(me) {
  return R.pipe(family, R.reject(equalsMe(me)))(me);
}

I'd like to pass me to a function down the pipe along with the value that family returns.

Tried a few things with R.useWith or R.converge with R.identity or R.__ (not even sure if I should be using that) but found nothing to work.

Solution

  • If I understand correctly family is a function that takes a person and returns a list of family members (including that person) e.g.

    family(2);
//=> [1, 2, 3]

    Then you want to create a function siblings which takes a person and returns only their siblings e.g.

    siblings(2);
//=> [1, 3]

    Personally I think your function would read slightly better if it was written this way:

    const siblings = me => reject(equals(me), family(me));

siblings(2);
//=> [1, 3]

    If you really wanted a pointfree version of it, you could use converge but I really don't think it is any better:

    const siblings = converge(reject, [unary(equals), family]);