Essentially what I want is to extract the byte size of the L3 cache from lscpu. The tricky part is that the units lscpu uses is not consistent across versions and what I need has to work with all versions (including the versions before the --bytes option was available). lscpu from what I can see will either use K, KiB, M or MiB so that is what I'm trying to parse.
Here is what lscpu outputs:
Architecture: x86_64
CPU op-mode(s): 32-bit, 64-bit
Byte Order: Little Endian
CPU(s): 16
On-line CPU(s) list: 0-15
Thread(s) per core: 1
Core(s) per socket: 1
Socket(s): 16
NUMA node(s): 1
Vendor ID: GenuineIntel
CPU family: 6
Model: 60
Model name: Intel Core Processor (Haswell, no TSX, IBRS)
Stepping: 1
CPU MHz: 2299.998
BogoMIPS: 4599.99
Virtualization: VT-x
Hypervisor vendor: KVM
Virtualization type: full
L1d cache: 32K
L1i cache: 32K
L2 cache: 4096K
L3 cache: 16384K
NUMA node0 CPU(s): 0-15
Flags: fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ss syscall nx pdpe1gb rdtscp lm constant_tsc rep_good nopl xtopology eagerfpu pni pclmulqdq vmx ssse3 fma cx16 pcid sse4_1 sse4_2 x2apic movbe popcnt tsc_deadline_timer aes xsave avx f16c rdrand hypervisor lahf_lm abm invpcid_single ssbd ibrs ibpb tpr_shadow vnmi flexpriority ept vpid fsgsbase tsc_adjust bmi1 avx2 smep bmi2 erms invpcid xsaveopt arat md_clear spec_ctrl
And this is what I have so far but can't seem to finish it off.
$ lscpu | awk '/L3 cache:/{print $3$4;next};/(M|MiB)$/{printf "%u\n", $3*(1024*1024);next};/(K|KiB)$/{printf "%u\n", $3*1024;next}'
0
32768
32768
4194304
16384K
Any ideas how to tweak my awk command to get this working?
Edit: My expected output would just be:
16777216
Really Cyrus' answer is the optimal, but if you're set on awk, try this:
awk -F: 'BEGIN{def=1024}/^L3/{if($2~/M/){def=def*def}; printf "%u\n", $2*def}'