This query is about creating a histogram where user gives an input and we calculate the number of times a word has occurred
I am not able to understand the solution
input = "Hello how are you? I am fine how are you"
text = input.to_s
words = text.split
frequencies = Hash.new(0)
words.each do |word|
frequencies[word] += 1
end
p frequencies
Output
{"Hello"=>1, "how"=>2, "are"=>2, "you?"=>1, "I"=>1, "am"=>1, "fine"=>1, "you"=>1}
[Finished in 527ms]
In the above code we are calculating the frequency of each word. but where are we storing it in the frequencies hash?
which part of the code is doing that?
If i include a print statement inside the block it only gives the frequency.. so how is the word itself getting stored..
My apologies in advance if this is a silly question but i am not able to understand how the assignment is happening at the back end-- if we print it (inside the block), its displaying only the frequency..
Thanks in advance for helping out..
Adding the word to the hash and increasing the counter happens in the line
frequencies[word] += 1
and that only works because when the key does not exist yet then 0 is returned because of how the hash was defined in this line
frequencies = Hash.new(0)
Btw when you take advantage of Enumerable#tally then you can solve the whole problem in just only line:
input.split.tally
#=> {"Hello"=>1, "how"=>2, "are"=>2, "you?"=>1, "I"=>1, "am"=>1, "fine"=>1, "you"=>1}