I know this should be easy but for some reason, I cannot get the result that I need. I have data that looks like this where 'raw_time' is read into a df in the date format yyyy-mm-dd hh:mm:ss. It looks like this:
dfdates =
1429029 1992-01-03 02:00:00
1429030 1992-01-03 01:00:00
1429031 1992-01-03 00:00:00
1429032 1992-01-02 23:00:00
1429033 1992-01-02 22:00:00
1429034 1992-01-02 21:00:00
1429035 1992-01-02 20:00:00
1429036 1992-01-02 19:00:00
1429037 1992-01-02 18:00:00
1429038 1992-01-02 17:00:00
1429039 1992-01-02 16:00:00
1429040 1992-01-02 15:00:00
1429041 1992-01-02 14:00:00
1429042 1992-01-02 13:00:00
1429043 1992-01-02 12:00:00
1429044 1992-01-02 11:00:00
I just need to convert each row to day of year. So the result in a new df would look like:
df_doy:
index day_of_year
1429029 3
1429030 3
1429031 3
1429032 2
1429033 2
1429034 2
1429035 2
1429036 2
1429037 2
1429038 2
1429039 2
1429040 2
1429041 2
1429042 2
1429043 2
1429044 2
thank you,
We have
df['day_of_year'] = pd.to_datetime(df[col]).dt.dayofyear
Or just output the day
df['day_of_year'] = pd.to_datetime(df[1]).dt.day