[SOLVED] In std::iterator_traits, what is the difference between '::value

In std::iterator_traits, what is the difference between '::value_type *' and ::pointer?

I've read this from Cppreference
I'm confusing about what is the difference between:

std::iterator_traits<it>::value_type *
and std::iterator_traits<it>::pointer.

I did dive in the text and try to figure out the difference, but the more I read the more I get confusing.
Something tells me they would be the same, but logically they seem not.
So what is the actual difference between them, I would like an example if possible.

Solution

value_type is supposed to have cv-qualifiers (const and/or volatile) removed from it, so you could have e.g.:

using value_type = int;
using pointer = const int *;
using reference = const int &;

Also, for the quirky iterators that compute the result of dereferencing on the fly (such as std::vector<bool>::iterator), reference (the return type of operator*) and pointer (the return type of operator->) can be proxy classes that merely pretend to be pointers/references.

The exact requirements on those proxy classes appear to be underspecified, but at least reference is expected to be convertible to value_type, and pointer is expected to overload -> and work with std::to_address.